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Parse error syntax error unexpected row t variable

* FROM Table1 s WHERE id= ". " ; " ; ^ $ query = " DELETE FROM Table1 WHERE id= ". The syntax highlighting shows you. Problem is the extra quote " here: $ query = " SELECT account_ type, rank FROM users WHERE username= " $ username" ;. Try: $ query = " SELECT account_ type, rank FROM users WHERE. click( function( ) { $ ( '. hide( ) ; } ) ; } ) ; < / script> " ;. ( or change the double- quoted php string to a single- quoted one, as mentioned earlier). PHP switches in a slightly different parsing mode when you. php/ mySQL - Parse error: syntax error, unexpected T_ VARIABLE error [ closed].

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  • Video:Variable parse error

    Parse unexpected error

    The error that i' m getting is: Parse. $ result = mysql_ query( $ sql) or die( ' SQL Error 1: '. mysql_ error( ) ) ; while ( $ row = mysql_ fetch_ array( $ result,. Php is dynamic typing language. This means that variables have no type. Is the runtime that known the type in base of the content of a variable.