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Error syntax error at or near do postgres

you can use procedural statements only inside function body in PostgreSQL. DO $ $ Declare test varchar; begin test : = ' teste' ; if ( char_ length( test) > 0) then RAISE NOTICE ' > > > % < < < ', test; end if; end; $ $ ;. What you need to do is to have string literal passed as parameter to psql. Here you need to use " because you can escape " ( quotation mark or double quote) inside " but you cannot escape ' ( apostrophe or single quote) inside '. That isn' t a complete statement. You need a CREATE FUNCTION statement if you' re trying to create a function, or a DO block if you' re trying to run a one- off procedure. For one- off DO blocks, it should look like. why do i get this syntax error? psql: upsert_ test_ log. sql: 7: ERROR: syntax error at or near " ON" LINE 5: ON CONFLICT ( activity_ name). According to the error code, your version does not support ON CONFLICT. テーブル名で使用しようとしている user は、 PostgreSQLの予約語です。 ダブル クォーテーションで囲んであげることでテーブル作成は出来ますが、 select文等を書く ときも、 ダブルクォーテーションで囲う必要があります。 create table " user". The foreign key reference needs to mention the table, even for a self- reference: ALTER TABLE employee ADD FOREIGN KEY ( manager) REFERENCES employee( emp_ id) ;.

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  • Video:Error near postgres

    Error error postgres

    In addition, the first insert doesn' t work because. You' re running on an old version of PostgreSQL. In general, if you get an unexpected syntax error on a keyword or PostgreSQL complains about a missing function that should obviously exist, the first thing to do is check that. DO LANGUAGE plpgsql. postgres= # alter user my- sys with password ' pass11' ; ERROR: syntax error at or near " - " LINE 1: alter user. I think the best you do is to drop that user and recreate without illegal identifier characters and without double.